First, we have to find the slope.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Let's replace the points (-10,-11) and (-8,-9).
[tex]m=\frac{-9-(-11)}{-8-(-10)}=\frac{-9+11}{-8+10}=\frac{2}{2}=1[/tex]Then, we use the point-slope formula to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \end{gathered}[/tex]Let's replace the point (-8,-9) and the slope 1.
[tex]\begin{gathered} y-(-9)=1(x-(-8)) \\ y+9=x+8 \\ y=x+8-9 \\ y=x-1 \end{gathered}[/tex]Hence, the equation that represents the table is
[tex]y=x-1[/tex]