What are the x and y-intercepts of the line described by the equation?2x + 4y = 12.4x-intercept = y-intercept =

The given equation is,
[tex]2x+4y=12.4[/tex]X-intercept
To solve for x-intercept we will equate y = 0.
[tex]\begin{gathered} 2x+4(0)=12.4 \\ 2x+0=12.4 \\ 2x=12.4 \\ \frac{2x}{2}=\frac{12.4}{2} \\ x=6.2 \end{gathered}[/tex]Y-intercept
To solve for y-intercept we will equate x = 0.
[tex]\begin{gathered} 2(0)+4y=12.4 \\ 0+4y=12.4 \\ 4y=12.4 \\ \frac{4y}{4}=\frac{12.4}{4} \\ y=3.1 \end{gathered}[/tex]Hence,
[tex]\begin{gathered} x-\text{intercept}=(6.2,0) \\ y-\text{intercept}=(3.1,0) \end{gathered}[/tex]