Question

Complete the third row of the table.Express the temperature in degrees Celsius to three significant figures.

Answer 1

Answer:

$T_2\text{ = 17.3}\degree C$

Explanation:

Here, we want to get the initial temperature

From Charles' law, we know that at constant pressure, the volume of a given mass of gas is directly proportional to its temperature

Mathematically, we can have this written as:

$\frac{V_1}{T_1\text{ }}=\frac{V_2}{T_2}$

We can rewrite the formula in terms of the missing value as follows:

$T_2\text{ = }\frac{V_2T_1}{V_1}$

Let us write out the values given, not forgetting that we have to convert the temperature value to Kelvin by adding 273.15 K

Thus, we have:

$\begin{gathered} V_1\text{ = 2.21 L} \\ T_1\text{ = 14.7 + 273.15 = 287.85 K} \\ V_2\text{ = 2.23 L} \\ T_2\text{ = ?} \end{gathered}$

Substituting these values in the re-written formula, we have it as:

$T_2=\text{ }\frac{2.23\times287.85}{2.21}\text{ = 290.455 K}$

Finally, what we have to do is to convert this temperature to degrees celsius by subtracting 273.15 K

We have this as:

$290.455\text{ - 273.15 = 17.3 }$