The table in the question is provided.
A linear function is written in the form:
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept.
The slope is calculated using the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
If we use the first two points, we can calculate the slope as follows:
[tex]\begin{gathered} (x_1,y_1)=(4,26) \\ (x_2,y_2)=(5,23) \\ \therefore \\ m=\frac{23-26}{5-4} \\ m=-3 \end{gathered}[/tex]
Therefore, for us to solve for a, we can use the slope formula but the slope must be -3:
[tex]\begin{gathered} (x_1,y_1)=(4,26) \\ (x_2,y_2)=(6,a) \\ \therefore \\ -3=\frac{a-26}{6-4} \\ -3=\frac{a-26}{2} \\ a-26=-3\times2=-6 \\ \therefore \\ a=-6+26 \\ a=20 \end{gathered}[/tex]
Therefore, the correct option is the LAST OPTION.