Question

3.Calculate the temperature when 8.5 L at 15.0 °C is compressedto 4.5L.

Answer 1

Answer:

The temperature is 7.94°C.

Explanation:

1st) To calculate the temperature, we can use the Charles's Law.

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

The given information is:

- V1: 8.5L

- T1: 15.0°C

- V2: 4.5L

- T2: this is what we have to calculate:

2nd) Replacing the values in the formula:

$\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{8.5L}{15.0\degree C}=\frac{4.5L}{T_2} \\ 0.567\frac{L}{\degree C}=\frac{4.5L}{T_{2}} \\ T_2=\frac{4.5L}{0.567\frac{L}{\degree C}} \\ T_2=7.94\degree C \end{gathered}$

Finally, the temperature is 7.94°C.