Question

Help! Also even though it looks blurry, just zoom in to see the full question

Answer 1

The matrix transformation of triangle XYZ with coordinates

$\begin{gathered} X=(-2,-2) \\ Y=(4,1) \\ Z=(0,6) \end{gathered}$

When dilated by a factor of 2.5 now becomes;

$\begin{gathered} 2.5\begin{bmatrix}{-2} & 4{} & 0{} \\ {-2} & {1} & {6}{}\end{bmatrix}=\begin{bmatrix}{2.5(-2)} & {2.5(4)} & {2.5(0)} \\ {2.5(-2)} & {2.5(1)} & {2.5(6)} \\ & {} & {}\end{bmatrix} \\ =\begin{bmatrix}{-5} & {10} & {0} \\ {-5} & {2.5} & {15} \\ {} & {} & {}\end{bmatrix} \end{gathered}$

ANSWER:

The correct vertices of the image now becomes;

$\begin{gathered} X^{\prime}=(-5,-5) \\ Y^{\prime}=(10,2.5) \\ Z^{\prime}=(0,15) \end{gathered}$