Given the system of equations:
[tex]\begin{cases}3x-4y=20 \\ 2x+4y=0\end{cases}[/tex]Add up both equations:
[tex]\begin{gathered} \begin{cases}3x-4y=20 \\ 2x+4y=0\end{cases}\rightarrow3x+2x-4y+4y=20+0 \\ \rightarrow5x=20 \end{gathered}[/tex]Solve for x,
[tex]\begin{gathered} 5x=20\rightarrow x=\frac{20}{5} \\ \Rightarrow x=4 \end{gathered}[/tex]Plug the value of x in equation 2 and solve for y,
[tex]\begin{gathered} 2x+4y=0\rightarrow2(4)+4y=0\rightarrow8+4y=0 \\ \rightarrow4y=-8\rightarrow y=-\frac{8}{4} \\ \Rightarrow y=-2 \end{gathered}[/tex]Thereby,
[tex]\begin{gathered} x=4 \\ y=-2 \end{gathered}[/tex]