Solve.(z-2)(z-1)=0(If there is more than one solution, separate them with commas.)= 0Z=80,0,...Ś

We have the equation:
[tex](z-2)(z-1)=0[/tex]There are a total of two options that complies the equation, as it is a product.
If the first term is 0, the equation is right.
But if the second term is 0, the equation is right too.
Then both are solutions.
So we have:
[tex]z-2=0[/tex][tex]z=2[/tex]And,
[tex]z-1=0[/tex][tex]z=1[/tex]Then we can conclude:
The two correct answers are z=2 and z=1
z=1,2 in the format asked.