all you need is in the photo please answer fast pleaseee pleaseeeeeeeeeeee4p+2g=963p+1g=60

The given equations are in standard form, first, write them in slope-intercept form.
"p" is the variable in the x-axis
"g" is the variable in the y-axis
First equation
[tex]\begin{gathered} 4p+2g=96 \\ 2g=96-4p \\ \frac{2g}{2}=\frac{96}{2}-\frac{4p}{2} \\ g=-2p+48 \end{gathered}[/tex]Second equation
[tex]\begin{gathered} 3p+1g=60 \\ g=60-3p \end{gathered}[/tex]Next, you have to determine two points for each equation, the easiest point to determine is the y-intercept, just replace the formula with p=0
For the second point, you can choose any value of p, for example, p=10
First equation
For p=0
[tex]\begin{gathered} g=-2p+48 \\ g=-2\cdot0+48 \\ g=48 \end{gathered}[/tex]The first point is (0,48)
For p=10
[tex]\begin{gathered} g=-2\cdot10+48 \\ g=-20+48 \\ g=28 \end{gathered}[/tex]The second point is (10,28)
Plot the points and link them with a line.
Second equation
For p=0
[tex]\begin{gathered} g=-3p+60 \\ g=-3\cdot0+60 \\ g=60 \end{gathered}[/tex]The first point is (0,60)
For p=10
[tex]\begin{gathered} g=-3\cdot10+60 \\ g=30 \end{gathered}[/tex]The second point is (10,30)
Plot both points and link them to determine the line