Respuesta :

The given equations are in standard form, first, write them in slope-intercept form.

"p" is the variable in the x-axis

"g" is the variable in the y-axis

First equation

[tex]\begin{gathered} 4p+2g=96 \\ 2g=96-4p \\ \frac{2g}{2}=\frac{96}{2}-\frac{4p}{2} \\ g=-2p+48 \end{gathered}[/tex]

Second equation

[tex]\begin{gathered} 3p+1g=60 \\ g=60-3p \end{gathered}[/tex]

Next, you have to determine two points for each equation, the easiest point to determine is the y-intercept, just replace the formula with p=0

For the second point, you can choose any value of p, for example, p=10

First equation

For p=0

[tex]\begin{gathered} g=-2p+48 \\ g=-2\cdot0+48 \\ g=48 \end{gathered}[/tex]

The first point is (0,48)

For p=10

[tex]\begin{gathered} g=-2\cdot10+48 \\ g=-20+48 \\ g=28 \end{gathered}[/tex]

The second point is (10,28)

Plot the points and link them with a line.

Second equation

For p=0

[tex]\begin{gathered} g=-3p+60 \\ g=-3\cdot0+60 \\ g=60 \end{gathered}[/tex]

The first point is (0,60)

For p=10

[tex]\begin{gathered} g=-3\cdot10+60 \\ g=30 \end{gathered}[/tex]

The second point is (10,30)

Plot both points and link them to determine the line

Ver imagen AleinaT400246
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