The initial expression is:
[tex]6m+3=\frac{2x-4}{2}[/tex]To solve for x, we need to multiply both sides by 2, as:
[tex]\begin{gathered} (6m+3)\cdot2=\frac{2x-4}{2}\cdot2 \\ 12m´+6=2x-4 \end{gathered}[/tex]Adding 4 on both sides, we get:
[tex]\begin{gathered} 12m´+6+4=2x-4+4 \\ 12m+10=2x \end{gathered}[/tex]Dividing by 2 on both sides:
[tex]\begin{gathered} \frac{12m+10}{2}=\frac{2x}{2} \\ 6m+5=x \end{gathered}[/tex]Answer: x = 6m + 5