18
Explanation
Direct variation describes a simple relationship between two variables, it can be defined by the expression
[tex]\begin{gathered} f(x)=kx \\ \text{where} \\ f(x)=\text{ y, } \\ \text{and k is a constant} \end{gathered}[/tex]Step 1
find the k value,
set the equation and solve for k
so
let
f(x)=64 when x=29
so
[tex]\begin{gathered} f(x)=kx \\ \text{replace} \\ 64=k\cdot29 \\ to\text{ solve for k, divide both sides by 29} \\ \frac{64}{29}=\frac{k\cdot29}{29} \\ \frac{64}{29}=k \end{gathered}[/tex]Step 2
now, set the equation:
with k=64/29 , the function would be
[tex]\begin{gathered} f(x)=kx \\ f(x)=\frac{64}{29}x \end{gathered}[/tex]finally, to check the f(x) when x= 8, just replace and calculate
[tex]\begin{gathered} f(x)=\frac{64}{29}x \\ f(8)=\frac{64}{29}\cdot8 \\ f(8)=\frac{512}{29} \\ f(8)=17.655 \\ \text{rounded} \\ f(8)=18 \end{gathered}[/tex]threfore, the answer is
18
I hope this helps you