[tex]\begin{gathered} \frac{a}{6}\text{ = }\frac{15}{2} \\ By\text{ cross multiplying, we have} \\ 2\text{ }\times\text{ a = 15 }\times\text{ 6} \\ 2a\text{ = 90} \\ a\text{ = }\frac{90}{2}\text{ = 45} \\ \text{ QUESTION 2} \\ \frac{10}{7}\text{ = }\frac{8}{K} \\ By\text{ cross multiplying, we have} \\ 10\text{ }\times\text{ k = 7 }\times8 \\ 10k\text{ = 56} \\ K\text{ =}\frac{56}{10} \\ K\text{ = 5.6} \end{gathered}[/tex]
