The first step is to express the equation in slope-intercept form which is;
y = mx + b
[tex]\begin{gathered} y+2=\frac{1}{2}(x-3) \\ y+2=\frac{1}{2}x-\frac{3}{2} \\ y=\frac{1}{2}x-\frac{3}{2}-2 \\ y=\frac{1}{2}x-\frac{3}{2}-\frac{4}{2} \\ y=\frac{1}{2}x-\frac{7}{2} \\ \text{The y-intercept is -3.5 (when x = 0)} \\ \text{The x-intercept is 7 (when y = 0)} \\ \text{The graph is now shown below;} \end{gathered}[/tex]
