Hello there. To solve this question, we have to remember some properties about histograms.
Given the following data, we want to determine:
649896
937097
746763
718057
807743
677852
659253
658762
654364
666450
a) The number of bins in the histogram
For this, we use the following formula:
[tex]\text{bins}=1+\lceil\log_2(n)\rceil[/tex]In this case, we have 30 values, hence
[tex]\text{b}\imaginaryI\text{ns}=1+\operatorname{\lceil}\operatorname{\log}_2(30)\operatorname{\rceil}\approx1+5=6[/tex]b) What size should your intervals be?
For this, we want to determine the width of a bin.
Using the following formula:
[tex]\text{ bin width }=\dfrac{\max(x)-\min(x)}{bins}[/tex]Where max(x) represents the maximum value in the data set, min(x) is the minimum value and bins is the number we found on a).
We get that max(x) = 98 and min(x) = 43, hence
[tex]\text{ bin width }=\dfrac{98-43}{6}=\dfrac{55}{6}\approx9.16[/tex]These are the answers to this question.