Question

Help please!What is the x-intercept of the line?X=-36 Y=-117X=-27 Y=-98X=-18 Y=-79

Answer 1

we nee to write the equation, the general form is

$y=mx+b$

where m is the slope and b the y-intercept

first find the slope

$m=\frac{y2-y1}{x2-x1}$

where (x2,y2) is a right point from (x1,y1)

we will use two points from the table ( -36 , -117 ) ( -27 , -98 )

so replacing

$\begin{gathered} m=\frac{-98-(-117)}{-27-(-36)} \\ \\ m=\frac{19}{9} \end{gathered}$

we replace the slope on the equation

$y=\frac{19}{9}x+b$

now repalce any point of the table on the equation to find b

I will use (-18,-79)

$\begin{gathered} (-79)=\frac{19}{9}(-18)+b \\ \\ -79=-38+b \\ \\ b=-79+38 \\ b=-41 \end{gathered}$

so, the y-intercept of the line is (0,-41) and the general euqation of the line is

$y=\frac{19}{9}x-41$