Question

a statistic class was asked about the city where they live the results are listed below that F equal Fort Pierce P equal Port St Lucie vehicle Vero Beach as equal Sebastian and Zoey equal Okeechobee

Answer 1

Given:

F = Fort Pierce

P = Port St. Lucie

V = Vero Beach

S = Sebastian

O = Okeechobee

From the details gotten from the class, the frequency of each is given below;

$\begin{gathered} F=5 \\ P=3 \\ V=10 \\ S=7 \\ O=5 \\ \text{Total frequency = 30} \end{gathered}$

To get the relative frequency,

$R\text{ elative frequency = }\frac{frequency}{\text{total frequency}}$

Hence, the relative frequency and percentage for;

Fort Pierce is;

$\begin{gathered} R\text{ elative frequency = }\frac{frequency}{\text{total frequency}} \\ R\text{ elative frequency = }\frac{5}{30}=0.167 \\ \text{Percentage = 0.167}\times100\text{ =16.7\%} \end{gathered}$

Hence, the relative frequency and percentage for;

Port St. Lucie is;

$\begin{gathered} R\text{ elative frequency = }\frac{frequency}{\text{total frequency}} \\ R\text{ elative frequency = }\frac{3}{30}=0.100 \\ \text{Percentage = 0.100}\times100\text{ =10.0\%} \end{gathered}$

Hence, the relative frequency and percentage for;

Vero Beach is;

$\begin{gathered} R\text{ elative frequency = }\frac{frequency}{\text{total frequency}} \\ R\text{ elative frequency = }\frac{10}{30}=0.333 \\ \text{Percentage = 0.333}\times100\text{ =33.3\%} \end{gathered}$

Hence, the relative frequency and percentage for;

Sebastian is;

$\begin{gathered} R\text{ elative frequency = }\frac{frequency}{\text{total frequency}} \\ R\text{ elative frequency = }\frac{7}{30}=0.233 \\ \text{Percentage = 0.233}\times100\text{ =23.3\%} \end{gathered}$

Hence, the relative frequency and percentage for;

Okeechobee is;

$\begin{gathered} R\text{ elative frequency = }\frac{frequency}{\text{total frequency}} \\ R\text{ elative frequency = }\frac{5}{30}=0.167 \\ \text{Percentage = 0.167}\times100\text{ =16.7\%} \end{gathered}$