The area of the trapezium is calculated as follows:
[tex]A=\frac{b_1+b_2}{2}\cdot h[/tex]
Where b1 and b2 are the lengths of the bases (the parallel sides) and h is the height (perpendicular to the bases).
The figure gives us: b1 = 16 yd, b2 = 20 yd, h = 10 yd. Substituting:
[tex]A=\frac{16\text{ yd}+20\text{ yd}}{2}\cdot10\text{ yd}[/tex]
Calculating:
[tex]\begin{gathered} A=18\text{ yd}\cdot10\text{ yd} \\ \\ \boxed{A=180\text{ }yd^2} \end{gathered}[/tex]
Answer: C) 180 yd^2
