Question

The number of moles of aluminum ions in 1.5 mol of Al203 equals

Answer 1

Answer:

3.0 moles of aluminum ions

Explanations:

An Aluminium oxide Al₂O₃ consists of;

• two ,aluminum cations 2Al³⁺ and;

,

• three ,oxygen anions 3O²⁻

Based on stoichiometry, one mole of aluminum oxide therefore contains;

• two ,aluminum cations 2Al³⁺ and;

,

• three ,oxygen anions 3O²⁻

Given the parameter:

Number of moles of aluminum oxide = 1.5 moles

The number of moles of aluminum ion is calculated as thus:

$\begin{gathered} \text{ Mols of Al}^{3+}=1.5moles\text{ of }Al_2O_3\times\frac{2\text{ moles of aluminum ion}_{}}{1\text{ mole of aluminum oxi}de} \\ \text{ Moles of Al}^{3+}=1.5_{}\times2\text{ moles of aluminum ion} \\ \text{ Moles of Al}^{3+}=3.0moles\text{ of aluminum ion} \end{gathered}$

Hence the number of moles of aluminum ions in 1.5 moles of Al₂O₃ is 3.0 moles