A Sno-Cone at the carnival has the shape of a hemisphere on top of an inverted cone. What is the volume ofthe sno-cone if its radius is 5.5 mm and the height of the conical portion is 9.7 mm?

Answer:
Volume = 655.73
Explanation:
The sno-cone is composed of a hemisphere and a cone; therefore, its volume is
[tex]V=V_{cone}+V_{hemisphere}[/tex]Now
[tex]V_{\text{cone}}=\frac{\pi r^2h}{3}[/tex]and the volume of the hemisphere is
[tex]V_{\text{hemisphere}}=\frac{2}{3}\pi r^3[/tex]Therefore,
[tex]V=V_{cone}+V_{hemisphere}[/tex][tex]\rightarrow V=\frac{\pi r^2h}{3}+\frac{2}{3}\pi r^3[/tex]putting in h = 9.7 mm and r = 5.5 mm gives
[tex]\begin{gathered} V=\frac{\pi(5.5)^2(9.7)}{3}+\frac{2}{3}\pi(5.5)^3 \\ \end{gathered}[/tex]which simplifies to give (rounded to the nearest hundreth)
[tex]V=655.73\operatorname{mm}^3[/tex]which is our answer!