Respuesta :

Given:

h= -t^2 + 8t + 115

Where:

h = height

When the diver enters the water , h= 0

0 = -t^2 + 8t + 115

a = -1

b= 8

c= 115

Apply quadratic equation:

[tex]\frac{-b\pm\sqrt[\placeholder{⬚}]{b^2-4ac}}{2a}[/tex]

Replacing:

[tex]\frac{-8\pm\sqrt[\placeholder{⬚}]{8^2-4(-1)(115)}}{2(-1)}[/tex][tex]\frac{-8\pm\sqrt[\placeholder{⬚}]{524}}{-2}[/tex]

negative:

[tex]\frac{-8-\sqrt[]{524}}{-2}=15.45[/tex]

positive

[tex]\frac{-8+\sqrt[\placeholder{⬚}]{524}}{-2}=-7.44[/tex]

Answer:

t = 15.45 s

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