How long will it take until the driver enters the water? Also how do you know?

Given:
h= -t^2 + 8t + 115
Where:
h = height
When the diver enters the water , h= 0
0 = -t^2 + 8t + 115
a = -1
b= 8
c= 115
Apply quadratic equation:
[tex]\frac{-b\pm\sqrt[\placeholder{⬚}]{b^2-4ac}}{2a}[/tex]Replacing:
[tex]\frac{-8\pm\sqrt[\placeholder{⬚}]{8^2-4(-1)(115)}}{2(-1)}[/tex][tex]\frac{-8\pm\sqrt[\placeholder{⬚}]{524}}{-2}[/tex]negative:
[tex]\frac{-8-\sqrt[]{524}}{-2}=15.45[/tex]positive
[tex]\frac{-8+\sqrt[\placeholder{⬚}]{524}}{-2}=-7.44[/tex]Answer:
t = 15.45 s