Question

What is the solution to the equation below? (Round your answer to twodecimal places)5ehx=35oA X=201B = 3.980C = 4220

Answer 1

$\begin{gathered} 5\cdot\ln x=3.5 \\ \ln x^5=3.5 \end{gathered}$$\ln x=\frac{3.5}{5}=.7$$e^{.7}=x=2.01$

The answer is A, x=2.01