Define the system of equations
[tex]\begin{gathered} 3x+2y=70 \\ x+4y=90 \end{gathered}[/tex]Where x is the price for a shirt and y is the price for a pair of pants
Solve using substitution method
[tex]\begin{gathered} 3x+2y=70 \\ 3x=70-2y \\ x=\frac{70-2y}{3} \end{gathered}[/tex][tex]\begin{gathered} x+4y=90 \\ \frac{70-2y}{3}+4y=90 \\ -\frac{2y}{3}+4y=90-\frac{70}{3} \\ \frac{10}{3}y=\frac{200}{3} \\ 10y=200 \\ y=\frac{200}{10} \\ y=20 \end{gathered}[/tex]Find x
[tex]\begin{gathered} x+4y=90 \\ x=90-4(20) \\ x=10 \end{gathered}[/tex]A shirt costs $10 and a pair of pants costs $20