Question

The triangle below is a right triangle, solve for z. Z 9 40

Answer 1

We will solve this by using the law of cosines as follows:

$c^2=a^2+b^2-2ab\cos (C)$

And we replace as follows (We have that the angles is 90 degrees from the triangles):

$z^2=40^2+9^2-2(40)(9)\cos (90)\Rightarrow z=\sqrt[]{40^2+9^2-2(40)(9)\cos(90)}\Rightarrow z=41$

So, the value of z is 41.