Respuesta :

[tex]\begin{gathered} \frac{-3(v^{-1})^5}{2v^{-1}}\text{ = -}\frac{3}{2}\frac{(v^{-5})}{v^{-1}}\text{ } \\ =-\frac{3}{2}(v^{-5-(-1))})\text{ =-}\frac{3}{2}(v^{-5+1})=-\frac{3}{2}v^{-4} \end{gathered}[/tex]

So we brought the numbers out and worked on v alone

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