Question

find the surface area of the tunnel created inside the block.

Answer 1

The surface area of the tunnel passing through the block is simply the curved surface area of the cylindrical shape.

The Surface Area is given by

$A=2\pi rh$

where the following are given from the question:

$\begin{gathered} r=\frac{4}{2}=2ft \\ h=4ft \end{gathered}$

Substituting these values:

$\begin{gathered} A=2\times\pi\times2\times4 \\ A=50.27 \end{gathered}$

Therefore, the surface area of the tunnel created inside the block is 50.27 ft² (50.27 square feet)