Respuesta :

[tex]\begin{gathered} We\text{ have 3 roots because we have a cubic equation} \\ 4x^3+4x^2-48x=0 \\ 4x\cdot(x^2+x-12)=0 \\ 4x\cdot(x-3)\cdot(x+4)=0 \end{gathered}[/tex]

Now, let's analyze each factor

4x=0

x=0

x-3=0

x=3

x+4=0

x=-4

Answer

x=0, x=3, x=-4

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