Answer:
[tex]f^{-1}(x)=\frac{x+2}{5}[/tex]Explanation:
Given the below function;
[tex]f(x)=5x-2[/tex]We can go ahead and find the inverse of f(x) following the below steps;
Step 1: Replace f(x) with y;
[tex]y=5x-2[/tex]Step 2: Interchange x and y;
[tex]x=5y-2[/tex]Step 3: Solve for y by adding 2 to both sides of the equation and dividing both sides by 5;
[tex]\begin{gathered} x+2=5y-2+2 \\ x+2=5y \\ \frac{x+2}{5}=y \\ y=\frac{x+2}{5} \end{gathered}[/tex]Step 4: Replace y with f^-1(x);
[tex]f^{-1}(x)=\frac{x+2}{5}[/tex]