Question

A testing chamber holds a 2.00 L sample of neon gas at 300.0 K. If the pressure is measured inside the chamber as 3.25 atm, how many moles of neon are present?____ mol Ne

Answer 1

Answer:

There are 0.26 moles of neon.

Explanation:

From the information in the exercise we know that:

- Volume (V): 2.00L

- Temperature (T): 300.0K

- Pressure (P): 3.25atm

Using the Ideal Gases Law formula, we can calculate the number of moles (n), by replacing the values of V, T and P:

$\begin{gathered} P*V=n*R*T \\ 3.25atm*2.00L=n*0.082\frac{atm*L}{mol*K}*300.0K \\ 6.5atm*L=n*24.6\frac{atm*L}{mol} \\ \frac{6.5atm*L}{24.6\frac{atm*L}{mol}}=n \\ 0.26mol=n \end{gathered}$

So, there are 0.26 moles of neon (0.3 rounded).