Use two points on the line to find the equation

To find the equation of the line, we would use two points (-3,0) and (3,2)
We use the equation of a line in 2 point form;
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]We input the points to obtain;
[tex]\begin{gathered} \frac{y-0}{x+3}=\frac{2-0}{3+3} \\ \frac{y}{x+3}=\frac{2}{6} \\ \text{cross multiply} \\ y=\frac{2}{6}(x+3) \\ y=\frac{2}{6}x+1 \end{gathered}[/tex]Therefore, the equation is standard form is;
[tex]y=\frac{2}{6}x+1[/tex]