ANSWER
1/4 n²
EXPLANATION
First, we distribute the exponent into the product,
[tex](2n^{-1})^{-2}=2^{-2}\cdot(n^{-1})^{-2}[/tex]
Negative exponents flip the fractions and exponents of exponents multiply,
[tex]2^{-2}\cdot(n^{-1})^{-2}=\frac{1}{2^2}\cdot n^{(-1)\cdot(-2)}=\frac{1}{4}n^2[/tex]
Hence, your answer is correct, 1/4n².
