Question

Solve the following system of linear equations by graphing:4x + y = 4x 48-3+ + 2y = -1

Answer 1

Given:

$\begin{gathered} -\frac{4}{3}x+y=4\ldots\text{ (1)} \\ -\frac{8}{3}x+2y=-1\ldots.\text{ (2)} \end{gathered}$

Equation (1) can be written as

$y=\frac{4}{3}x+4\ldots\text{ (3)}$

Equation (2) can be written as

$\begin{gathered} 2y=\frac{8}{3}x-1 \\ y=\frac{4}{3}x-\frac{1}{2}\ldots\text{ (4)} \end{gathered}$

By equating equation(3) and equation(4)

$\begin{gathered} \frac{4}{3}x+4=\frac{4}{3}x-\frac{1}{2} \\ 4\ne-\frac{1}{2} \end{gathered}$

There is no solution.