Question

How many combinations are possible without repeats for C(6,2)

Answer 1

The combinations can be calculated using the following formula:

$C(n,r)=\frac{n!}{r!(n-r)!}$

In our case n=6 and r=2, then:

$C(6,2)=\frac{6!}{2!(4)!}=\frac{2*3*4*5*6}{2*2*3*4}=\frac{5*6}{2}=15$

Hence the answer is 15