Question

Solve each equation by using the square root property. 2x^2–3=7.

Answer 1

$x=\pm\sqrt[]{5}$

Explanation

$2x^2-3=7$

Step 1

add 3 in both sides

$\begin{gathered} 2x^2-3=7 \\ 2x^2-3+3=7+3 \\ 2x^2=10 \\ \end{gathered}$

Step 2

divide both sides by 2

$\begin{gathered} 2x^2=10 \\ \frac{2x^2}{2}=\frac{10}{2} \\ x^2=5 \\ \end{gathered}$

Step 3

then take the square root of both sides and solve for the variable

$\begin{gathered} x^2=5 \\ \sqrt[]{x^2}=\text{ }\pm\sqrt[]{5} \\ x=\pm\sqrt[]{5} \end{gathered}$