Area of the triangle PQR can be determined as,
[tex]\begin{gathered} \Delta=\frac{1}{2}\times QP\times RS \\ =\frac{1}{2}\times8\text{ cm}\times RP\sin 39^{\circ} \\ =\frac{1}{2}\times8\text{ cm}\times15\operatorname{cm}\times\sin 39^{\circ} \\ =37.759cm^2 \end{gathered}[/tex]
Thus, the required area of the triangle to the nearest tenth is 37.8 square centimeters.
