Question

solve this problem pls

Answer 1

For the matrix equatiion

$2X+A=B$

subtracting A from both sides gives

$2X=B-A$

now,

$B-A=\begin{bmatrix}{-7} & {-8} & {} \\ {-2} & {6} & {} \\ {4} & {4} & {}\end{bmatrix}-\begin{bmatrix}{-3} & {0} & {} \\ {0} & {3} & {} \\ {-6} & {6} & {}\end{bmatrix}$$B-A=\begin{bmatrix}{-7--3} & {-8-0} & {} \\ {-2-0} & {6-3} & {} \\ {4--6} & {4-6} & {}\end{bmatrix}$$B-A=\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix}_{}$

Hence,

$2X=\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix}_{}$

Dividing both sides by 2 gives

$X=\begin{bmatrix}{-10} & {-8} & {} \\ {-2} & {-3} & {} \\ {10} & {-2} & {}\end{bmatrix}_{}\cdot\frac{1}{2}$$X=\begin{bmatrix}{-5} & {-4} & {} \\ {-1} & {-\frac{3}{2}} & {} \\ {5} & {-1} & {}\end{bmatrix}$

which is our answer!