SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
Case A:
Line A :
Two points : ( -3, 4) and (-1,0)
[tex]\text{slope,m = }\frac{y_2-y_1}{x_2-x_1}=\text{ }\frac{0-4}{-1-(-3)\text{ }}\text{ =}\frac{-4}{-1+3}=\frac{-4}{2}=-2\text{ (COR}\R ECT)[/tex]
Case B:
Line B:
Two points: ( -1, 4 ) and ( 1, 0 )
[tex]\text{slope, m = }\frac{y_2-y_1}{x_2-x_1}=\text{ }\frac{0-4}{1\text{ - (-1)}}=\frac{-4}{1+1}=\frac{-4}{2}=\text{ -2 (COR}\R ECT)[/tex]
Case C:
Line C:
Two points: ( 1, 4 ) and ( -1, 0 )
[tex]\text{slope, m = }\frac{y_2-y_1}{x_2-x_1}=\text{ }\frac{0-4}{-1-1}=\frac{-4}{-2}=\text{ 2 ( NOT COR}\R ECT)[/tex]
Case D:
Line D:
Two points : ( 3,4 ) and ( 1,0)
[tex]\text{slope, m =}\frac{y_2-y_1}{x_2-x_1}=\frac{0-4}{1-3}=\frac{-4}{-2}=2\text{ (NOT COR}\R ECT)[/tex]
CONCLUSION:
We have seen clearly that:
Line A and Line B have a slope of -2
