JaceonO391584 JaceonO391584
  • 30-10-2022
  • Mathematics
contestada

I need help please. Solve:2.6 + x < 8.3

Respuesta :

KeylinE18290 KeylinE18290
  • 30-10-2022

We need to solve:

[tex]2.6+x<8.3[/tex]

The first step is to subtract "2.6" on both sides:

[tex]\begin{gathered} 2.6+x-2.6<8.3-2.6 \\ x+2.6-2.6<5.7 \\ x<5.7 \end{gathered}[/tex]

On the number line, we have:

Notice that the the dot must be on "5.7" and it must be an opened dot.

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