The expression is 7³ * 7⁻⁵
To solve this you have to apply the law of exponents
[tex]a^b\cdot a^c=a^{(b+c)}[/tex]So for the expression it is
[tex]7^3\cdot7^{(-5)}=7^{(3-5)}=7^{-2}[/tex]The negative exponent "-2" means that the value is inverted following the law:
[tex]\times^{-1}=\frac{1}{x}[/tex][tex]7^{-2}=\text{ }\frac{1}{7^2}[/tex]Answer 7⁻²= 1/7²