Respuesta :

Given:

3x + 1 < 10

Solve:

Subtract 1 from both sides:

3x + 1 - 1 < 10 - 1

3x < 9

Divide both sides by 3:

[tex]\begin{gathered} \frac{3x}{3}<\frac{9}{3} \\ \\ x<3 \end{gathered}[/tex]

Graph x<3:

ii) -2y + 22 < 10

SUbtract 22 from both sides:

Ver imagen YahyeU714153
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