Question

A circuit with a battery, a 6 Ω resistor, a 15 Ω resistor, and a 27 Ω resistor in parallel. The total voltage is the system is 10.0 V. What is the current through the battery?

Answer 1

Resistors in parallel:

R1=6 Ω

R2=15 Ω

R3=27 Ω

Total voltage = V = 10 V

To find the total R:

$\frac{1}{RT}=\frac{1}{R1}+\frac{1}{R2}+\frac{1}{R3}$$\frac{1}{RT}=\frac{1}{6}+\frac{1}{15}+\frac{1}{27}$$\frac{1}{RT}=\frac{73}{270}$$270\cdot1=RT\cdot73$$\frac{270}{73}=RT$

$RT=3.7$

RT=3.7Ω

Ohm's Law

V=I x R

I = V/R = 10 V / 3.7 Ω = 2.7 A