3 clear values are the mean and at least two values of 74 since it is the mode
[tex]\begin{gathered} 74 \\ 74 \\ 80 \\ a \\ b \end{gathered}[/tex]if the range is 30 the difference between 74 and greater number is 30
then
[tex]\begin{gathered} b-74=30 \\ b=104 \end{gathered}[/tex][tex]\begin{gathered} 74 \\ 74 \\ 80 \\ a \\ 104 \end{gathered}[/tex]now we apply the mean to find a
we add all numbers and divide between 5 to obtain the mean(85)
[tex]\begin{gathered} \frac{74+74+80+104+a}{5}=85 \\ \\ \frac{332+a}{5}=85 \end{gathered}[/tex]and solve for a
[tex]\begin{gathered} 332+a=85\times5 \\ 332+a=425 \\ a=425-332 \\ a=93 \end{gathered}[/tex]Finall data is
[tex]\begin{gathered} 74 \\ 74 \\ 80 \\ 93 \\ 104 \end{gathered}[/tex]