Part A
Initial population of parrot in the animal sanctuary = 20 parrots
The population is increasing by 5 parrots per year.
let
number of years = x
y = population of parrot
The function can be represented as
[tex]y=5x+20[/tex]Part B.
Initial population of snake in the sanctuary = 24
Each year 4 more snakes are born
let
number of year = x
y = population of the snake
The function can be represented below
[tex]y=24+4x[/tex]Part C
Number of parrot in 10 years
[tex]\begin{gathered} y=5x+20 \\ y=5(10)+20 \\ y=50+20=70 \\ Number\text{ of parrot in 10 years = 70} \end{gathered}[/tex]Number of snakes in 10 years
[tex]\begin{gathered} y=4x+24 \\ y=4(10)+24 \\ y=40+24=64 \\ Number\text{ of snakes in 10 years = }64 \end{gathered}[/tex]Part D
The number of year where the number of parrot and snakes are the same can be calculated below
[tex]\begin{gathered} 5x+20=4x+24 \\ 5x-4x=24-20 \\ x=4 \end{gathered}[/tex]The snakes and the parrot will be equal in population after 4 years time.