ShalynT79375 ShalynT79375

30-10-2022
Mathematics

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SorenI151602 SorenI151602

30-10-2022

[tex]\begin{gathered} 16H-4 \\ 4(4H-4) \end{gathered}[/tex]

we can multiply the factor on the second equation, then multipli 4H and -4 by 4

[tex]\begin{gathered} 4\times4H-4\times4 \\ 16H-16 \end{gathered}[/tex]

the expressions arent equivalent

becuase 16H-16 is different to 16H-4

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