Question

Check number 1 please and help me solve the rest.

Answer 1

In this session we will focus on question 5. We are asked to simplify the following expression

$(\frac{\placeholder{⬚}\text{ -1}}{2}x^3y^0)(6x^2y^3)(\text{ -3y\rparen}$

First, recall that any non zero number, raised to the 0th power is equal to 1. So we have

$y^0=1$

Also, recall the property of exponents that given a,b,c and we have that

$a^b\cdot a^c=a^{b+c}$

What we will do is that we are going to group the expression into another expressions, organized by the same variable and the constants. So we get

$(\frac{\placeholder{⬚}\text{ -1}}{2}\cdot6\cdot(\text{ -}3))(x^3\cdot x^2)(y^3\cdot y)$

so applying the property on each expression, and operating, we get

$(9)(x^5)(y^4)=9x^5y^4$