Suppose that f is an even function, g is odd, both are integrable on [-7, 7], and we know that….

SOLUTION:
Step 1:
In this question, we have given the following:
Step 2:
The details of the solution are as follows:
Suppose that f is an even function, g is odd, both are integrable on [-7, 7], and we know that:
[tex]\begin{gathered} \int ^7_0f(x)dx\text{ = 5, Recall that f(x) is an even function} \\ \text{Then} \\ \int ^7_{-7}f(x)dx\text{ = 2 ( 5 ) = 10} \end{gathered}[/tex][tex]\begin{gathered} \int ^7_0g(x)dx\text{ = 4. 5 , Recall that g(x) is an odd function} \\ \text{Then } \\ \int ^7_{-7}g(x)dx\text{ =4. 5 - 4. 5 }=\text{ 0} \end{gathered}[/tex]Finally, we can see that:
[tex]\int ^7_{-7}\lbrack\text{ f(x) + g ( x) }\rbrack dx\text{ = 10 + 0 = 10}[/tex]