Question

In circle J with mLHJK 54 and HJ = 13 units find area of sector HJK. Round to the nearest hundredth. K H J

Answer 1

we have a circle first we will calculate the whole area of the circle using the next formula

$A=\pi r^2$

where r= 13 units

$A=\pi(13)^2=530.93\text{ square units}$

Then we have 54° we need to divide between 360 In order to know the part of the circle we have

$\frac{360}{54}=\frac{20}{3}$

so in order to know the area of the sector HJK we will divide the area between 20/3

$A_S=\frac{A}{\frac{20}{3}}=\frac{530.93}{\frac{20}{3}}=79.63$