Answer
Explanation
Given:
mm
A.
To determine the measure of [tex]\begin{gathered} m\angle TRQ+m\angle QRS=180 \\ 145+m\angle QRS=180 \\ \text{Simplify and rearrange} \\ m\angle QRS=180-145 \\ m\angle QRS=35\degree \end{gathered}[/tex]
Therefore, m
B.
To determine the measure of [tex]\begin{gathered} m\angle QRS+\angle S+\angle Q=180 \\ 35+y+4y=180 \\ \text{Simplify and rearrange} \\ 35+5y=180 \\ 5y=180-35 \\ 5y=145 \\ y=\frac{145}{5} \\ y=29\degree \end{gathered}[/tex]Now, we plug in y=29 into m[tex]\begin{gathered} m\angle Q=4y \\ m\angle Q=4(29) \\ m\angle Q=116\degree \end{gathered}[/tex]Therefore, m
