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0,4,-4
Explanation
[tex]3c^3-48c=0[/tex]Step 1
we can see both terms in the equation have c, so C is a common factor.
Let's factorize it
hence
[tex]\begin{gathered} 3c^3-48c=0 \\ c(3c^2-48)=0 \\ \text{therefore, we have 2 factors} \\ (c)((3c^2-48)=0 \end{gathered}[/tex]Step 2
now, when the product of 2 numbers equal zero:
[tex](c)(3c^2-48)=0[/tex]is because
1) one of the two numbers is zero
2) both numbers are zero
so
[tex]\begin{gathered} C\text{ =0} \\ is\text{ a solution } \end{gathered}[/tex]Step 3
finally, we need to check when the second factor is zero
so
[tex]\begin{gathered} 3c^2-48=0 \\ \text{add 48 in both sides} \\ 3c^2-48+48=0+48 \\ 3c^2=48 \\ \text{divide both sides by 3} \\ \frac{3c^2}{3}=\frac{48}{3} \\ C^2=16 \\ \text{take the square root in both sides} \\ \sqrt{C^2}=\sqrt{16} \\ C=\pm4 \end{gathered}[/tex]therefore, the answer is
[tex]0,4,-4[/tex]