A ball is dropped from a tower. The table shows the heights of the ball's bounces, which form a geometric sequence. Describe in words how you would find the height of the next bounce?

to find the height of the next bounce, just replace the x value in the function
[tex]f(x)=36x^2-228x+392[/tex]the heigth of next bounce is 56 ft}
Explanation
Step 1
find the equation of the quadratic function, so
i) set the equations
a quadratic function is in the form
[tex]f(x)=ax^2+bx+c[/tex]so, we can replace the known coordinates for find a, b and c
so
a)
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ a)(1,200),\text{ so} \\ 200=a(1)^2+b(1)+c \\ 200=a+b+c\rightarrow equation(1) \end{gathered}[/tex]b)
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ b)(2,80) \\ 80=a(2)^2+b(2)+c \\ 80=4a+2b+c\rightarrow equation(2) \end{gathered}[/tex]c)
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ c)(3,32) \\ 32=a(3)^2+(3)x+c \\ 32=9a+3b+c\rightarrow equation\text{ (3)} \end{gathered}[/tex]Step 2
solve the equations
[tex]\begin{gathered} 200=a+b+c\rightarrow equation(1) \\ 80=4a+2b+c\rightarrow equation(2) \\ 32=9a+3b+c\rightarrow equation\text{ (3)} \end{gathered}[/tex]a) isolate x in equation (1) and (2) , then let c= c
so
[tex]\begin{gathered} 200=a+b+c\rightarrow equation(1) \\ c=200-a-b \\ and \\ 80=4a+2b+c\rightarrow equation(2) \\ c=80-4a-2b \\ c=c\text{ , so} \\ 200-a-b=80-4a-2b \\ 200-80=-4a-2b+a+b \\ 120=-3a-b\rightarrow equation(4) \end{gathered}[/tex]b)isolate x in equation (1) and (3) , then let c= c
[tex]\begin{gathered} 32=9a+3b+c \\ c=32-9a-3b \\ C=C,\text{ so} \\ 200-a-b=32-9a-3b \\ 300-32=-9a-3b+a+b \\ 168=-8a-2b\rightarrow equation(5) \end{gathered}[/tex]c) now, use equation (4) and equation(5) to find a and b
[tex]\begin{gathered} 120=-3a-b\rightarrow equation(4) \\ 168=-8a-2b\rightarrow equation(5) \end{gathered}[/tex]i)isolate b in both sides, then let b=b
[tex]\begin{gathered} 120=-3a-b\rightarrow equation(4) \\ b=-3a-120 \\ \text{and} \\ 168=-8a-2b\rightarrow equation(5) \\ 168+8a=-2b \\ b=\frac{168+8a}{-2} \\ b=-84-4a \\ B=B,\text{ so} \\ -3a-120=-84-4a \\ -3a+4a=-84+120 \\ a=36 \end{gathered}[/tex]replace to find b
[tex]\begin{gathered} b=-3a-120 \\ b=-3(36)-120 \\ b=-108-120=-228 \\ b=-228 \end{gathered}[/tex]finally, replacei n equation (1) to find c
[tex]\begin{gathered} 200=a+b+c\rightarrow equation(1) \\ 200=36-228+c \\ 200=192+c \\ 200+192=c \\ c=392 \end{gathered}[/tex]therefefore,
[tex]f(x)=36x^2-228x+392[/tex]Step 3
now, we have the function
[tex]f(x)=36x^2-228x+392[/tex]so
to find the height of the next bounce, just replace the x value in the function
[tex]f(x)=36x^2-228x+392[/tex]so, when bounce = 4,
let
x=4
[tex]\begin{gathered} f(x)=36x^2-228x+392 \\ f(4)=36(4)^2-228(4)+392 \\ f(4)=56 \end{gathered}[/tex]so, the heigth of next bounce is 56 ft
56 ft
I hope this helps you