in the figure below, two seconds are drawn to a circle from an exterior point E. Suppose that EZ = 16.8, EX = 14, and EW =35. Find XY.

Knowing that two secants are drawn to a circle from an exterior point, you need to use the Intersecting Secant Theorem.
Based on the Intersecting Secant Theorem, you can write the following equation:
[tex]EZ\cdot EW=EX\cdot EY[/tex]Knowing that:
[tex]\begin{gathered} EZ=16.8 \\ EX=14 \\ EW=35 \end{gathered}[/tex]Substitute those values into the equation:
[tex](16.8)(35)=(14)\cdot EY[/tex]Solve for EY:
[tex]\begin{gathered} 588=14EY \\ EY=\frac{588}{14} \\ EY=42 \end{gathered}[/tex]Notice that:
[tex]EY=EX+XY[/tex]Then you can substitute values and solve for XY:
[tex]\begin{gathered} 42=14+XY \\ 42-14=XY \\ XY=28 \end{gathered}[/tex]The answer is:
[tex]XY=28[/tex]